Given x = 2t + 5, y = t<sup>2</sup> – 2; then dy/dx is calculated as

EXERCISE 8 A Q.17
Q.17) Given x = 2t + 5, y = t² – 2; then dy/dx is calculated as

CORRECT

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x = 2t + 5,
Diff.w.r.t. t we get,
dx/dt = 2(1) + 0 = 2
y = t² – 2;
Diff.w.r.t. t we get,
dy/dt = 2t
now dy/dx = (dy/dt)/(dx/dt)
∴ dy/dx = 2t/2 = t
Answer : (a)

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